CCS+UT2级考试真题200705

CCS+UT2级考试真题200705
CCS+UT2级考试真题200705

CCS 超声波 II 级理论考题答案(2007.5旅顺)

一. 选择题(每选2分,共70分)

1. 超声波的波长: λ=C/f ,又f=1/T(周期).周期:完成一个全振动所需时间.

A .与介质的声速和频率成正比;

B .等于声速和频率的乘积;

C .等于声速与周期的乘积; D.与声速和频率无关.

2.超声波入射到异质界面时,可能发生: A .反射; B .折射; C .波型转换; D.以上都可能.

3.下列直探头,在钢中指向性最好的是

o D o C o B D 58.418

5/9.570;16.5204/70;8.9143/9.57070=======θθλ

θ A .2.5P20Z ; B .3P14Z ; C .4P20Z ; D.5P18Z .

4.超声波的扩散衰减主要取决于: A .波阵面的几何形状;B .材料的晶粒度; C .材料的粘滞性; D.以上全部.

5.外径为D,内径为d 的空心圆柱体,以相同的灵敏度在内壁和外圆探测,如忽略耦合差异,则底

波高度比为: D

d x F P P d D x F p P D B D B λλ2:;2:00==外内外壁探内壁探 d

D d D D d

d D P P B B ===22外内 A .1; B .(D/d)1/2; C .((D-d)/2)1/2; D. D/d .

6.聚焦探头声透镜曲率增大时,透镜聚焦变化为: A .增大; B .不变; C .减小; D.无规律.

见书P.193 F=2.2r 当声透镜曲率增大时,其曲率半径减小,从公式可知F 减小,即透镜聚焦减小.

7.超声波检测系统的盲区是指A .主声束扫描不到的区域; B .近场内距离;

C .1.6N 区域; D.被始脉冲宽度覆盖区所代表的距离.

8.复合材料探伤,由于两介质声阻抗不同,在界面处有回波出现,为了检查复合层结合质量,下

列哪条叙述是正确的: A.两介质声阻抗接近,界面回波小,不易检查;

B.两介质声阻抗接近,界面回波大,容易检查;

C.两介质声阻抗差别大,界面回波大,不易检查;

D.两介质声阻抗差别大,界面回波小,容易检查

9.在超声波检测中一般不允许使用”抑制”旋钮,其原因是: A .使仪器垂直线性变化; B .动态范围变小;

C .灵敏度降低; D.以上全部.

10.超声波检测系统的灵敏度取决于: A .探头、高频脉冲发生器和放大器性能; B .同步发生器性能;

C .仪器的重复频率; D.仪器的阻塞特性.

11.在探测条件相同的情况下,直径比为2的两个实心圆柱体,其曲底面回波相差:

实心圆柱体曲底面回波与大平底回波规律相同

dB x D P x D P P P B B 62lg 202

14214lg 20lg 2022012021==??=λπλπ A .12dB ; B .9dB ; C .6dB ; D. 3dB.

12.超声波检测系统的盲区大小受下列哪些因素影响:

A .系统的发射强度;

B .调节灵敏度;

C .仪器阻塞特性; D.以上均是.

13.探头软保护膜和硬保护膜相比,突出的优点是:

A .透声性好;

B .材质衰减小;

C .有利消除耦合差异;D.以上均是.

14.超声波检测系统组合性能的常用指标为:

A .水平和垂直线性;

B .灵敏度余量和动态范围;

C .噪声电平和分辨力V 型槽; D.灵敏度和盲区; E 以上均非.

15.在厚板焊缝检测用试块中,人工反射体一般应选:

A .短横孔;

B .长横孔;

C .横通孔; D.以上均可.

16.直探头纵波探伤时,工件上下表面不平行会使底波变化,结果是

: A .底波降低甚至消失;B .底波变宽; C .底波变窄; D.以上均非.

17.超声波检测中下列哪种参考反射体与入射声束角度无关

: A .平底孔; B .平底槽; C .V 型槽; D.横孔.

18.超声波检测常规方法中,可检测的缺陷尺寸一般认为不小于:

见书P.85倒一行

A .波长的1/4;

B .波长的1/3;

C .波长的1/2; D.以上均非.

19.

在脉冲反射法探伤中,可根据什么判断缺陷的存在: A .缺陷回波; B .底波或参考回波的减弱或消失;

C .接收探头接收到的能量的减弱; D.A 和B 都对.

20.板厚T=150mm 的钢板,

作周边超声波检测时,周边扫查范围一般为: A .50mm ; B .75mm ; C .150mm ; D.按标准规定.

21.焊缝检验中,对一缺陷环绕扫查,

其动态波形包络线是方形的,则缺陷性质可估判为: 见书P.96动态波形图.

A .条状夹渣;

B .气孔或圆形夹渣;

C .裂纹; D.以上A 和C.

22.

在焊缝斜探伤中,哪种看法是错的: A .一般来说,根部未焊透,反射波高度比气孔高;

B .用单斜探头直射法探伤时,内部未焊透的反射波高度往往很低;

C .裂纹因为是平面状缺陷,所以反射波总是很高;

D. 未溶合缺陷,两侧探伤具有不对称性.

23.锻件接触法探伤中,如果探伤仪的”

重复频率”调得过高,可能发生A .荧光屏”噪声”信号过高; B .时间线倾斜;

C .始脉冲消失; D.容易出现”幻想波”.

以下试题按照《CCS 无损检测人员资格认证规范》(2000)的有关要求进行选择

: 24.陆上各类各级无损检测人员资格证书的有效期为: A .3年; B .4年; C .5年.

25.拟更新证书的持证人,

应向考试中心提出证书更新的书面申请,一般为:

A.证书有效期满前6个月;B.证书有效期期满之前;

C.证书有效期期满之后; D.随时.

26.某操作人员取得UT I级证书,现领导安排其按高级人员制定的工艺规程并在II级人员的指导下进行检测工作,同时独立负责对仪器定时检查水平线性、垂直线性等仪器检查工作.问

领导的工作安排是否合适?

A.合适;B.不合适.

以下试题按照CB/T3559-94的有关要求进行选择:

27.按CB/T3559标准要求,探伤仪与斜探头组合分辨力(Z值)在CSK-IA或STB-A2试块上的

φ1.5×4两孔测定,其Z值应: 标准4.4

A.>6dB; B.>15dB;C.≤6dB; D.≤15dB; E.无规定.

28.每格2分) 标准4.2 A.0.5%;B.1%;C.2%; D.3%; E.5%.

29.标准4.3

A.>1;B.>2;C.≤1; D. ≤2; E.无规定.

30.母材板厚25mm,标准7.1

A.1~4MHz;B.2~5MHz;C.3~6MHz; D.4~7MHz.

31.时基线调节时,最大检测距离至少调整到示波屏基线满刻度的标准8.2

A.50%;B.75%;C.80%; D.90%.

32.CB/T3559标准规定,初探伤灵敏度为: 标准12.1

A.不低于MRL线;B.不低于ARL线;C.不低于DRL线;D.不低于φ3线.

33.若缺陷回波位于DRL线和MRL线之间,有一个峰幅,测长应采用什么方?: 标准13.4.2 A.6dB相对灵敏度法; B. 端点峰值降低6dB相对灵敏度法;C.MRL线绝对灵敏度法; D. 端点峰值降低MRL线绝对灵敏度法. 34.根据缺陷的波高和指示长度及分布状态,焊缝质量可分为Ⅰ~Ⅴ级,当缺陷回波高于ARL

线时均应评为: 标准15.2

A.Ⅰ级;

B.Ⅱ级;

C.III级;

D.Ⅳ级;

E.Ⅴ级.

(注:选择题与2006.05旅顺考题同21题)

二.简答题(共10分)

1.何谓超声波检测灵敏度?通常调节超声波检测灵敏度的方法有哪几种?(5分)

答:超声波检测灵敏度是指在确定的探测范围的最大声程处发现规定大小缺陷的能力。而在具体操作中是要求:按标准或技术条件规定的检验灵敏度要求为依据,将与该要求对应的人工反射体(指定类型、大小和声程)最高回波调到基准波高(如80%),则检测灵敏度符合要求。

调节检测灵敏度的方法有:

⑴试块调整法:将与检测灵敏度要求对应的试块上人工反射体最高回波调至基准波高(如80%),则检测灵敏度就调好(当试块与试件的表面耦合和材质衰减有差异时,需在调节灵敏度时考虑此表面耦合和材衰差的dB值);

⑵试件底波调整法:根据声压公式计算的试件底面回波与同深度人工反射体(如平底孔)回波的分贝差(ΔdB),将试件底面回波先调至准波高度(如80%),再增益ΔdB,则灵敏度调好;

⑶距离-波幅曲线调整法:根据标准规定在相应试块上作出距离-波幅曲线,再将标准规定的人工反射体(如船标规定为φ3-16dB )的最高回波调至基准波高(如船标规定调至测长线),再加上试件与试块的表面耦合补偿dB 值,则检测灵敏度调好。

2.简述钢板探伤时引起底波消失的几种可能原因?(5分)

答:⑴探伤灵敏度调的太低;

⑵探头耦合不好(钢板表面有氧化皮和浮锈,钢板表面太粗糙等); ⑶探头损坏;

⑷探头线断路;

⑸仪器接收电路有故障;

⑹钢板晶粒粗大;

⑺钢板中有严重的密集缺陷;

⑻钢板中存在大于声束截面的缺陷;

⑼钢板底面太粗糙或锈蚀严重。

三.计算题(共20分)

1.试计算5P14SJ 探头,在水中(C L =1500m/s)的指向角和近场长度?(5分) 解:mm f C 3.05

5.1===λ ?=?==5.114

3.070700D λ

θ mm D N 1633

.041442

2=?==λ 答:5P14SJ 探头在水中的指向角为1.5°, 近场区长度为163mm 。

2.对钛钢复合板,在复合层一侧作接触法检测.已知钛与钢的声阻抗差约为40%,试计算复合层界面回波与底波相差多少dB?(5分)

解:设钢的声阻抗为Z 2=1,则钛的声阻抗为Z 1=0.6.

25.06

.016.011212=+-=+-=Z Z Z Z r p dB r r p p p p s B 5.1125

.09375.0lg 20|1|lg 20lg 202==-==? 答:复合层界面回波与底波相差11.5dB 。

3.用2.5P20Z 直探头检测厚度为300mm 的钢锻件(C L =5900m/s),衰减

系数α=0.01dB.

(1) 如用试块(衰减可忽略)上的深200mm,φ=4mm 平底孔调节探伤灵敏度(φ=2mm),两者波高dB 差为多少?(5分)

(2) 如用厚度为200mm 的试块(锻件与试块衰减相同,但耦合差5dB)底波,如何调节探伤灵敏度?(5分)

解:A. 36.25

.29.5===f C λ mm D N 4.4236

.242042

2=?==λ 3N =127.2<200 故可用声压公式计算:

dB X X X X X X dB f j f j f j j f 252000230001.02200

23004lg 4022200

23004lg 40)(2lg

40=??-??+??=-+??=-+=?试工αααφφ 答:两者的波高相差25dB 。

B. dB X X X X p p dB B f B f f B 4710001.02200

214.330036.22lg 20)(22lg 20lg 2022212=??+????=-+==?απφλ

ΔdB 2 = 5dB

ΔdB=ΔdB 2+ΔdB 1=52 dB

答:将试块底波调节至基准波高(如80%),再增益52 dB ,则灵敏度符合要求。

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