大学物理实验绪论答案
实验绪论课作业答案
1、(1) 44.02 m (2) 12.40±0.01 m (3) 13.59 kg
(4) 0.289m (5) 5.27 m (6) 5.61×104 m 2
3、V = 4
πh ?d 2 = 1.963×10-4 m 3
方法一 :?V = |h V ??|?h +|d V ??|?d = 4π(d 2 ??h + 2h ?d ??d) =0.01×10-4 m 3
方法二 :V V ? = h h ? + d
d ?2 = 0.005 ?V = 0.005 ? V= 0.01×10-4 m 3
V = ( 1.96 ± 0.01 )×10-4 m 3 B =
V
V ?= 0.5% P=99.7% 方法三 :方和根传递法
?V=()()2222d d V h h V ???? ????+???? ???? =4π()()()22242d hd h d ?+?=0.008×10-4 m 3
V = ( 1.963 ± 0.008) ×10-4 m 3 B =
V V ?= 0.4% P=99.7% 4、 (1) ±0.5 mm (2) ±1℃ (3) ±0.01g
(4) ±0.05 mm (6) ±1.5 mA (或 ±2 mA)
5、 L =1.449×10-2 m
L σ=())110(102--∑i i L L = 0.004×10-2 m
L=(1.449±0.004) ×10-2 m B = 0.3% P =68.3% L=(1.45±0.01) ×10-2 m B = 0.7% P =99.7%
6、 R x =2
1R R ?R O = 92.5Ω
①. 方法一 :?R x = |
1R R x ??|?R 1 +|2R R x ??|?R 2 +|0R R x ??|?R 0 = 2R R o ?R 1 +22
1R R R o
?R 2+21R R ?R 0 =0.0925+ 0.0925+ 0.1 = 0.3Ω
方法二 :x x R R ? = 11R R ? + 22R R ?+ 0
0R R ? = 0.003 ?R x = 0.003?R x = 0.3Ω
R x = 92.5±0.3Ω B = 0.3% P = 99.7%
②. ?R x =()()()202
022222121R R R R R R R R R x x x
????? ????+????? ????+????? ????=0.16Ω ≈0.2Ω
R x = 92.5±0.2Ω B = 0.2% P = 99.7%
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