2019年郑州市初中中招适应性测试(郑州二模带答案)免费版

2019年郑州市初中中招适应性测试(郑州二模带答案)免费版
2019年郑州市初中中招适应性测试(郑州二模带答案)免费版

2019年初中中招适应性测试

化学试题卷

注意:本试卷分试题卷和答题卡两部分。考试时间50分钟,满分50分。考生应首先阅读试题卷及答题卡上的相关信息,然后在题卡上作答,在试题卷上作答无效。交卷时只交答题卡 相对原子质量:H-1 C-12 N-14 O-16 S-32 C1-35.5 Mg-24 K-39

Ca-40 Mn-55 Fe-56 Cu-64 Zn-65 Ag-108

一、选择题〔本包括14个小题,每小題1分,共14分,毎小题只有一个选项符合题意)

1.下列变化类型与“钢铁生锈”相同的是 ( )

A.水的蒸发

B.镁的燃烧

C.干冰升华

D.海水晒盐

2.下列有关水的说法不正确的是( )

A.过氧化氢溶液中含有水分子

B.用肥皂水可以区分软水和硬水

C.有水生成的反应一定是中和反应

D.电解水实验可以证明水是由氢、氧两种元素组成的

3.下列食品中富含蛋白质的是( )

A.鱼肉

B.蔬菜

C.稻米

D.芝麻油

4.根据下图所示实验分析得出的结论不正确的是( )

5.“何以解忧,唯有杜康”就是对我省杜康酒的赞美。“酒越陈越香醇”是指酒在存放过程中可生成有香味的乙酸乙酯(C 4H 8O 2),下列有关乙酸乙酯的说法正确的是( )

A.乙酸乙酯的相对分子质量为(12×4+1×8+16×2)g

B.乙酸乙酯由4个碳原子、8个氢原子和2个氧原子构成

C.生成乙酸乙酯的过程中原子的种类、数目均未发生改变

D .乙酸乙酯中碳元素的质量分数=%10029

12

6.下列法不利于减轻环境污染的是( )

A.燃煤脱硫后使用

B.农药化肥的合理使用

C.开发氢能、可燃冰

D.露天烧桔杆制取草木灰

7.下图是元素周期表的一部分。下列有关说法错误的是( )

A. 原子序数为14的元素为硅

B. 磷原子的最外层电子数为15

C.三种元素的原子中铝易失电子

D.相同质量的三种元素的单质含原子数最多的是铝

8.配制一定溶质量分数的氯化钠溶液,可导致所配制的溶液浓度一定偏小的操作是()

A.用固体氯化钠配制6%的氯化钠溶液,量水时俯视刻度

B.用固体氯化钠配制6%的氯化钠溶液,称量时右盘忘记放纸片

C.用固体氯化钠配制6%的氯化钠溶液,搅拌溶解时有液体溅出

D.用6%的氯化钠溶液稀释为3%的氯化钠溶液,量6%氯化钠溶液时仰视刻度

9.A、B、C三种物质的溶解度曲线如右图所示。下列分析正确的是()

A. t1℃时,A,C两种物质的饱和溶液中溶质的质量相等

B.将A,B、C三种物质的饱和溶液变为不饱和溶液,可采

用升温的方法

C.将t2℃时A、B、C三种物质的饱和溶液降温至t1℃,所得

溶液的溶质质量分数的大小芙系是B>C=A

D.t2℃时,把A、B、C三种物质各25g分别入50g水中均得到饱和溶液,但溶质和溶剂

的质量比不相等

10.分类法是化学学习的重要方法之一,下列分类正确的是( )

A.单质:金刚石、水银、干冰

B.有机物;碳酸钠、醋酸,酒精

C.混合物:空气、石油、天然气

D.清洁能源:核能、太阳能、汽油

11.鉴别下列物质的方法,不正确的是()

12.实验室可用“高锰酸钾、氯酸钾、双氧水”分解制取氧气。关于这三个反应原理,下列说法正确的是()

A.都需要加催化剂

B.都有两种元素的化合价发生了变化

C.都生成氧化物

D.生成等量的O2消耗KMnO4的质量最大

13.将一定量的锌粉加入到硝酸银和硝酸铜的混合溶液中,充分反应后过,得到固体和蓝色溶液,加入锌粉的质量与洗涤、干燥后的固体质量相等。下列说法不正诵的是()

A.固体中一定含有银和铜,可能含有锌

B.滤液中一定含有Zn(NO3)2、Cu(NO3)2

C.若原混合液中含有硝酸铝,则反应前后固体的质量仍相等

D.反应中溶液的质量先变小后交大,但反应前溶液质量仍相等

14.有一包镁粉和氧化镁的混合物共25g,与一定量的稀硫酸恰好完全反应得到溶液,所得溶液中溶质的质量为60g,则原混合物中氧元素的质量为()

A.8g

B.10g

C.12g

D.13g

二、填空题(本题包括6个小题,每空1分,共16分)

15.化学源于生活,井服务于生活。

(1)冰箱中放入活性炭除异昧,利用了活性炭的性.

(2)碳酸氢钠是治疗胃酸过多症的一种药剂,请用化学方程式表示其反应原理. 16.用下图所示实验探究可燃物燃烧的条件(已知:白磷的着火点为40℃)

(1)能证明“温度达到可燃物着火

点是燃绕的条件之一”的一组对比

实验是(填序号)

(2)能证明“可燃物燃烧需要氧气”的实验现象是.

17.工业制镁的方法为:

18.

(1)生石灰转化为石灰乳的化学方程式为.

(2)上述流程中不包含的基本反应类型是.

(3)氢氧化镁与盐酸反应的微观实质是.

18.右图为验证Na2O2性质的实验,将A中产生的潮湿CO2通入到足量的Na2O2粉末中,充分反应,已知:Na2O2与水作用生成一种碱和O2,与CO2作用生成碳酸盐和O2

(1)A装置还可以用来制取的一种气体是.

(2)B中发生反应的化学方程式为(只写1个);

(3)若由C装置收集反应后的气体,请把C装置中的导管补画完整.

19.2019年9月全国少数民族运动会将在郑州举行。场馆建设中用到了大量的铜、铁、铝等金属材料。已知:铝能与氢氧化钠溶液反应,铁、钢不能与氢氧化钠溶液反应。把上述三种金属样品分别编号为X,Y、Z.若把X、Y、Z分别放入稀硫酸中,则X、Y溶解,Z 不溶解,另取X、Y分别放入氢氧化钠溶液中,Y溶解、X不溶解。请回答:

(1)X与Z的硫酸盐溶液反应的化学方程式为;

(2)Y与硝酸银溶液反应的化学方程式为。

20.右图是某反应的微观示意图,已知的化学式为HClO,是一种酸。

(1)该反应前后化合价没有发生变化的元素符号为;

(2)该反应中参加反应的单质与氧化物的质量比为;

(3)上述反应发生后加人NaOH溶液,发生反应的化学方程式为;.

三、简答题(本题包括4个小题,共10分)

21.(2分)在化学实验中,很多因素对实验现象成结果都有影响.

(1)请举例说明反应物的浓度不同,反应现象不同。

(2)相同温度下,碘分别在等量的水和汽油中溶解性不同,这个实例说明了什么?

22.(2分)右图为测定空气中氧气含量的实验。

(1)请写出D中试管内主要气体的化学式;

(2)能证明空气中O2含量的实验现象是什么?

23.(3分)为了除去粗盐中CaCl2、MgCl2、Na2SO4等可溶性杂质,需进行如下操作:①溶解;②依次加入过量的BaCl2、NaOH、Na2CO3溶液;③过滤;④加入适量盐酸;⑤蒸发、结晶。[提示:Mg(OH)2、BaSO4、BaCO3难溶于水;微溶物不形成沉淀]

(1)请写出操作②中加入Na2CO3溶液后,生成沉淀的化学式;

(2)操作④中加入适量盐酸的目的是什么?

(3)操作④中若加入过量盐酸也不会影响精盐的纯度,为什么?

24.(3分)右图中,甲、乙、丙、丁都含有铁元素,甲是氧化物,其中铁元素质量分数为70%;乙是黑色粉末丙和丁是含两种元素的盐,反应③为化合反应。请写出

(1)X的名称。

(2)①对应的化学方程式。

(3)③①对应的化学方程式。

四、综合应用题(共10分)

25.下图是利用数字化仪器测定CO 2含量的探究实验.

(1)按照图A所示连接实验装置,检查该装置气密性的方法是. (2)用装置A制取CO2气体,并分别用排水法和排空气法收集两锥形瓶气体备用,其中用排空气法收集时,应选用的装置为(填B或C)

(3)采用D图装置,将注射器中等量、等浓度的氢氧化钠溶液分别注入用排水法和排空气法收集的CO2气体的锥形瓶内(NaOH溶液均过量),得到如右图所示的压强随时间变化的曲线图。请用化学方程式说明锥形瓶内压强变化的原因.

(4)该实验说明收集到CO2的含量较高(填“排水法”或“排空气法”),请结合右图说明你的理由:

(5)请设计实验,证明反应进行到300s时,锥形瓶内溶液中溶质的成分。

(6)向盛有12g石灰石(杂质不参与反应)样品的锥形瓶中,加入100g稀盐酸,充分反应后,测得溶液呈酸性,锥形瓶内固体与溶液的总质量为107.6g,请计算样品中碳酸钙的质量.

2019年九年级适应性测试化学

参考答案及评分细则

注意事项:

1.答出其他合理答案,请参照评分标准给分。

2.没有特别要求写化学式的,写化学式或名称均给分。

3.关于化学方程式给分:

“化学式错误”0分。

“化学式正确,但配平、条件、沉淀或气体符号有1项错误”得0.5分。

“化学式正确,且配平、条件、沉淀或气体符号全部符合要求”得1分。

一、选择题(每小题1分,共14分)

1.B

2.C

3.A

4.A

5.C

6.D

7.B

8.B

9.D 10.C 11.C 12.D 13.A 14.D

二、填空题(每空1分,共16分)

15.(1)吸附(2)NaHCO3 + HCl==NaCl + H2O+ CO2↑

16.(1)A、C

(2)B中的白磷不燃烧,C中的白磷燃烧

17.(1)CaO + H2O == Ca(OH)2

(2)置换反应

(3)氢离子与氢氧根离子反应生成水分子

18.(1)氧气或氢气(答案合理即可)

(2)2Na2O2 + 2CO2 == 2Na2CO3+O2或2Na2O2 + 2H2 O == 4NaOH+O2↑

(3)

19.(1)Fe + CuSO4 == FeSO4+ Cu

(2)Al + 3AgNO3 == Al(NO3)3 + 3Ag

20.(1)H、O

(2)71:18

(3)NaOH + HCl == NaCl + H2O NaOH + HClO == NaClO + H2O(答案合理即可)三、简答题(共10分)

21.(1)硫在空气中燃烧产生淡蓝色火焰,在氧气中燃烧产生蓝紫色火焰。(1分)

(答案

合理即可)

(2)同一种物质在不同溶剂中的溶解性不同。(1分)

22.(1)N2(1分)

(2)进入试管中水的体积约占试管容积的1/5。(1分)

23.(1)CaCO3、BaCO3

(2)除去多余的NaOH和Na2CO3 。(1分)

(3)蒸发过程中HCl逸出。(1分)

24.(1)盐酸(1分)

(2)3CO + Fe2O3

高温

═══2Fe + 3CO2(1分)(答案合理即可)

(3)2FeCl2 + Cl2 == 2FeCl3(1分)

四、综合应用题(共10分)

25.(1)用止水夹夹紧胶皮管,轻推或轻拉注射器活塞,松开活塞后,观察活塞是否回到原来的位置。(1分)(答案合理即可)

(2)B (1分)

(3)2NaOH + CO2== Na2CO3 + H2O (1分)

(4)排水法(1分),注入氢氧化钠溶液后,排水法收集到的气体,锥形瓶内压强变化较大(1分)

(5)取锥形瓶内溶液少量于试管中,加入足量的CaCl2溶液,有白色沉淀生成,说明

原溶液中含有碳酸钠,向上层清液中加入酚酞溶液,溶液变红,说明原溶液中含有氢氧化钠。(2分)(答案合理即可)

(6)解:设样品中碳酸钙的质量为x。

CO2的质量:100g + 12g – 107.6g = 4.4g (1分)

CaCO3 + 2HCl==CaCl2 + H2O + CO2↑(1分)

100 44

x 4.4g

100

44=

x 4.4 g

x = 10 g (1分)答:样品中碳酸钙的质量为10 g。

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